Question

A tree is 20 √3 meters length. Find the angle of elevation, if its top from a point 20
meters away from its foot.​

Answer 1

Answer: 30°

tan A = opp side / adj side

= 20√3/20

20 get cancelled from both numerator and denominator

tan A = √3

Therefore angle A is 60° (tan 60°=√3)

Therefore angle of elevation = 90°-60° = 30°

Answer 2

A TREE IS 20√3

POINT 20 METERS AWAY FROM IT'S FOOT

TAN=OPP SIDE/ADJ SIDE

=20√3/20(20 CANCEL)

=√3

(TAN 60°=√3)

SO, ANGLE OF ELEVATION IS 60°