A tree is breaken due to storm and the broken part touches the ground making an angle of 30 degree with the ground the distance between the foot of the tree and to the point where the top touches the ground is 8m. Find the height of the treee
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firstly make a right triangle ABC in which BC=8m(base) and AC =20m and angle C is 30°
ab/bc= tan30°
ab/8=1/ root 3
ab= 8/root3 .......... 1)
again AC/BC=sec 30°
AC/8=2/root3
AC= 2/root3×8
AC = 16/root3..............2)
height of the tree= AB+BC
=8/root3+ 16/root3=24/root3
then after rationalize this we get 8root3
ab/bc= tan30°
ab/8=1/ root 3
ab= 8/root3 .......... 1)
again AC/BC=sec 30°
AC/8=2/root3
AC= 2/root3×8
AC = 16/root3..............2)
height of the tree= AB+BC
=8/root3+ 16/root3=24/root3
then after rationalize this we get 8root3
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