A tree is broken at a h of 9m above the ground and its top touches the ground at a distance of 12m frim root
Find l of ladder
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Answer:
Let A’CB be the tree before it broken at the point C and let the top A
′
touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B.
AB=12 m and BC=5 m
Using Pythagoras theorem,
In ΔABC
(AC)
2
=(AB)
2
+(BC)
2
(AC)
2
=(12)
2
+(5)
2
(AC)
2
=144+25
(AC)
2
=169
AC=
169
AC=13 m
Hence, the total height of the tree(A
′
B) =A
′
C+CB=13+5=18m.
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