a tree is broken at a height 6 m from the ground and its top touches the ground at a distance of 8 m from the base of the tree. find the original height of the tree.
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Its top touches the ground at a distance of 8 m from the base of the tree. So, Base = 8 m. Original height = 10+6 = 16 m.
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6^2+8^2=36+64=√100=10
total height =10+6=16 m
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