Question

A tree is broken at a height 6 metre from the ground and it is top touches the ground at a distance of of 8 metre from the base of a tree. Find the original height of a tree

Answer 1

Answer:

height of tree = 10 + 6 = 16 meter

Step-by-step explanation:

Given problem can be represented as a right triangle with remaining part of the tree as hypotonus.

remaining part = √{6² + 8²}

= √100

= 10 meter

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Answer 2

Answer:

16

Step-by-step explanation:

To find the length of broken part, we will use pythagoras theorem because whole scenario is looking like a triangle.

So, we have still stand tree's height i.e. 6 metres

and base length = 8 metres

Now, According to pythagoras theorem,

hypotenuse^2 = base^2 + height^2

hypotenuse^2 = 8^2 + 6^2

                        = 64 + 36

                        = 100

So, hypotenuse = squareroot( 100 )

                          = 10 metres

Here, Hypotenuse is broken part i.e. 10 metres and remaining part of tree's height is 6 metres.

Hence, original height of tree is (10 + 6) metres i.e. 16 metres