A tree is broken at a height of 12 m from the ground and its top touches the ground at a distance of 9 m from the base of the tree. Find the original Height of the tree.
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Answer:
- Original height of tree is 18 m
Step-by-step explanation:
Given:
- A tree is broken at a height of 12 m from the ground
- Its top touches the ground at a distance of 9 m from the base of the tree.
To Find:
- Original height of tree
Solution:
Let ∆ABC be the right traingle, right angles at B .
Since tree is vertical
- ∠B = 90°
AB = 5 m
BC = 12 m
Using, Phytgeores Theorem,
➠ (AC)² = (AB)² + (BC)²
➠ (AC)² = (12)² + (5)²
➠ (AC)² = 144 + 25
➠ (AC)² = 169
➠ AC = 13 m
Original height of tree = AB + AC
Original height of tree = 5 + 13 = 18 m
Hence,
- Original height of tree is 18 m
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