A tree is broken at a height of 20m from the ground and its top touches the ground at a distance 15m from the base of the tree. Find the original height of the tree.
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Answered by
1
Answer:
tree broken height = 20 metre
distance of ground = 15 metre
so, 20÷15 = 1.333…
no need to add this
Step-by-step explanation:
basic
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Answered by
0
Answer:
Ans is 25
Explanation:
Let BD be the original height of tree.
∴AD=AC
In △ABC
AC
2
=AB
2
=BC
2
=15
2
+8
2
=225+64
=289
⇒AC=17m
⇒AD=17m
∴ Original height of tree =(17+8)m=25m
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