A tree is broken at a height of 4m from the ground. Its top touches the ground at
a distance of 3m from the base of the tree. Find the original height of the tree.
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Answer:
Let's use the Pythagros therom =
(s2)+(s2)=(hypotenuse2)
Here the dimensions given are = 3m, 4m
So, =
32 + 42 = hypotenuse2
9 + 16 = 25
25 = 52
the total height of the tree =
3m + 5m = 8m
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