A tree is broken at a height of 4m from the ground its top touch the ground at a distance of 3m from the base of the tree find the original height of tree
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Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.
AB=12m and BC=5m
Using Pythagoras theorem, In ΔABC
(AC)2+(AB)2+(BC)2
⇒(AC)2=(12)2+(5)2
⇒(AC)2=144+25
⇒(AC)2=169
⇒AC=13m
Hence, the total height of the tree=AC+CB=13+5=18m.
i hope it is helpful to you
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