Question

A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree.

Answer 1

Answer:

17 m

Step-by-step explanation:

5m +12 m =17m it is the right answer bro

Answer 2

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)² +(AB)² +(BC)²

⇒(AC)² =(12)²+(5)²

⇒(AC)² =144+25

⇒(AC)² =169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.