A tree is broken at a height of 5 m from the ground and its top touches the ground
at a distance of 12 m from the base of the tree. Find the original height of the tree.
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2
Answer:
5 +12
17
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According to the given statement the sketch we get is right angled triangle RQ2 = PR2 + PQ2 = 52 + 122 = 25 + 144 = 169 ∴ RQ = 169−−−√169 = 13m
∴ The original height of the tree is PR + RS = 5 + 13 = 18
Thereforw the original height of the tree is 18 m.
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