Question

A tree is broken at a height of 5 m from the ground and its top touches the

ground at a distance of 12 m from the base of the tree. Find the original height

of the tree.​

Answer 1

Answer:

Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B. Hence, the total height of the tree(A'B) = A'C + CB = 13 + 5 = 18 m

Answer 2

Answer:

The total height of the tree=AC+CB = 13+5 = 18m.

Step-by-step explanation:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB = 12m and BC = 5m

(AC)² +(AB)² + (BC)²

(AC)²= (12)²+ (5)²

(AC)²= 144+25

(AC)²= 169

⇒AC = 13m

Hence, the total height of the tree = AC+CB = 13+5 = 18m.

           I hope this answer will help you........