A tree is broken at a height of 5 m from the ground and its top touches
the ground at a distance of 12 m from the base of the tree. Find the original
height of the tree
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Answer:
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Step-by-step explanation:
Let A’CB be the tree before it broken at the point C and let the top A′ touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B.
AB=12 m and BC=5 m
Using Pythagoras theorem,
In ΔABC
(AC)2=(AB)2+(BC)2
(AC)2=(12)2+(5)2
(AC)2=144+25
(AC)2=169
AC=169
AC=13 m
Hence, the total height of the tree(A′B) =A′C+CB=13+5=18m.
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