Question

A tree is broken at a height of 5 m from the ground and its body touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree.

Answer only if you know​

Answer 1

Answer: 18m

Step-by-step explanation:Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)  

2+(AB)  

2 +(BC)  

2 ⇒(AC)  

2 =(12)  

2 +(5)  

2

 

⇒(AC)  

2

=144+25

⇒(AC)  

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.

Answer 2

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)

2

+(AB)

2

+(BC)

2

⇒(AC)

2

=(12)

2

+(5)

2

⇒(AC)

2

=144+25

⇒(AC)

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.