A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree.
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Answer:
original height of the tree is 13m.
Step-by-step explanation:
hypotenuse = base square + height square
= 12 square(12 x12) + 5 square(5 x 5)
= 144 + 25
= 169
= square root of 169
= 13m
Hence, the total height of the tree(A’B) = A’C + CB = 13 + 5 = 18 m.
hope this will help.
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