A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree
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aditi22006:
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Hey buddy , let 2 will be square bcs the option is not given
So,
AC2= AB2+BC2
AC2=(5)2+(12)2
AC2=25+144
AC2=169
AC= (underoot of 169)
=13m
Original height of the tree=(5+13)
=18m
HOPE IT HELPS U...
PLS MARK AS BRAINLIEST...
So,
AC2= AB2+BC2
AC2=(5)2+(12)2
AC2=25+144
AC2=169
AC= (underoot of 169)
=13m
Original height of the tree=(5+13)
=18m
HOPE IT HELPS U...
PLS MARK AS BRAINLIEST...
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