Question

a tree is broken at a height of 5 metre from the ground and its top touches the ground at a distance of 12 m from the base of the tree find the original height of the tree​

Answer 1

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)

2

+(AB)

2

+(BC)

2

⇒(AC)

2

=(12)

2

+(5)

2

⇒(AC)

2

=144+25

⇒(AC)

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.

Answer 2

Answer and Step-by-step explanation:

According to the given statement the sketch we get is right angled triangle:

RQ = PR² + PQ²

= 5² + 12²

= 25 + 144 = 169

∴ RQ = 169

RQ = √169 = 13m

∴ The original height of the tree is PR + RS = 5 + 13 = 18 meter.