a tree is broken at a height of 5 metre from the ground and its top touches the ground at a distance of 12 m from the base of the tree find the original height of the tree
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you may need a calculator for this problem
but anyways here is the solution
but anyways here is the solution
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Step-by-step explanation:
Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.
AB=12m and BC=5m
Using Pythagoras theorem, In ΔABC
(AC)2 +(AB) 2 +(BC) 2
⇒(AC) 2 =(12) 2 +(5) 2
⇒(AC) 2 =144+25
⇒(AC) 2 =169
⇒AC=13m
Hence, the total height of the tree=AC+CB=13+5=18m.
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