Question

A tree is broken at a height of 5m from the ground and its top

touches the ground at a distance of 12m from the base of the tree. Find

the original height of the tree.​

Answer 1

Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B. Hence, the total height of the tree(A'B) = A'C + CB = 13 + 5 = 18 m.

Answer 2

tree height = 18cm

Step-by-step explanation:

after this tree fall on groud form a right angle ∆

therefor, we know that by (pythagorous theoram)

h² = b²+p²

h² = 12²+5²

h² = 144+25

h =√(169)

h = 13

so height of tree = 13 + 5

= 18cm