Math, asked by studyguru2579, 2 months ago

A tree is broken at a height of 5m from the ground and its top touches the ground at a distance of 12m from the base of the tree. Find the orignal height of the tree

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Answers

Answered by adi0043579
2

Answer:

The total height of the tree is 18m

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Answered by saanvigrover2007
1

Let A'CB represent the tree before it is broken at the point C and let the top A' touches the ground at A after it broke Then  \triangle ABC is the right angled triangle, right angled at B.

Then,

{ \underline{\purple{ \sf{AB = 12m  \: and  \: BC = 5m}}}}

Using Pythagoras Theorem in  \triangle ABC

 \rm \green{(AC)^{2}  = (AB)^{2}   +  BC^{2} }

 \sf{(AC)^{2} =  {12}^{2}  +  {5}^{2} } \\  \sf{(AC)^{2}  = 144 + 25}

 \sf{(AC)^{2} = 169}

\sf \blue{AC=  \sqrt{169} }

\sf { \underline{\fbox{\pink{AC = 13m}}}}

 \sf{Original  \: height \: of \: tree \: = 5 +13 =} \sf{\Large{\underline{\fbox{\red{18m}}}}}

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