A tree is broken at a height of 5m from the ground and its top touches the
ground at a distance of 12m from the base of the tree . Find the original height
of the tree .
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Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B. Hence, the total height of the tree(A'B) = A'C + CB = 13 + 5 = 18 m
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