A tree is broken at a height of 5m from the ground and its top touches the ground at a distance of 12m from the base of the tree. find the original height of the tree
Answers
Answer:
Let A’CB be the tree before it broken at the point C and let the top A’ touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B.
AB = 12 m and BC = 5 m
Using Pythagoras theorem,
In ΔABC
(AC)²=(AB)²+(BC)²
(AC)²=(12)²+(5)²
(AC)²=144+25
(AC)²=169
AC = √169
AC= 13 m
Hence, the total height of the tree(A’B) = A’C + CB = 13 + 5 = 18 m.
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Answer:
Step-by-step explanation:Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.
AB=12m and BC=5m
Using Pythagoras theorem, In ΔABC
(AC)
2
+(AB)
2
+(BC)
2
⇒(AC)
2
=(12)
2
+(5)
2
⇒(AC)
2
=144+25
⇒(AC)
2
=169
⇒AC=13m
Hence, the total height of the tree=AC+CB=13+5=18m.