Question

A tree is broken at a height of 5m from the ground and its top touches the ground at a distance of 12m from the base of the tree. find the original height of the tree​

Answer 1

ANSWER

18m

Step-by-step explanation:

we got perpendicular =5m

and the base=12m

Now we apply pythogoreus theorum, which says

(H)²=(P)²+(B)²

(H)²=(5)²+(12)²

(H)²=25+144

H=√169

H=13

we got hypotneus as 13m and the perpendicular is 5M so when add both we get the original height which is

18m

Answer 2

Answer:

• Original height of tree is 18 m

Step-by-step explanation:

Given:

• A tree is broken at a height of 12 m from the ground
• Its top touches the ground at a distance of 9 m from the base of the tree.

To Find:

• Original height of tree

Solution:

Let ∆ABC be the right traingle, right angles at B .

Since tree is vertical

• ∠B = 90°

AB = 5 m

BC = 12 m

Using, Phytgeores Theorem,

➠ (AC)² = (AB)² + (BC)²

➠ (AC)² = (12)² + (5)²

➠ (AC)² = 144 + 25

➠ (AC)² = 169

➠ AC = 13 m

Original height of tree = AB + AC

Original height of tree = 5 + 13 = 18 m

Hence,

• Original height of tree is 18 m

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