Question

A tree is broken at a height of 5m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. find the original height of the tree

Answer 1

Let A’CB represents the tree before it broken at the point C and let the top A’ touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB = 12 m and BC = 5 m

Using Pythagoras theorem,

In ΔABC

(AC)^2=(AB)^2+(BC)^2

⇒ (AC)^2=(12)^2+(5)^2

⇒ (AC)^2=144+25

⇒ (AC)^2=169

⇒ AC = 13 m

Hence, the total height of the tree = AC + CB = 13 + 5 = 18 m.

Answer 2

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