Question

a tree is broken at a height of 6 m from the ground and it's top touches the ground at a distance of 8m from the base. find the original height of the tree
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Answer 1

16 m

Step-by-step explanation:

We are given that a tree is broken at a height of 6 m from the ground

So, Right triangle is formed

So. Perpendicular = 6 m

Its top touches the ground at a distance of 8 m from the base of the tree.

So, Base = 8 m

Hypotenuse^2 = Perpendicular^2+Base^2Hypotenuse

2

=Perpendicular

2

+Base

2

Hypotenuse^2 = 6^2+8^2Hypotenuse

2

=6

2

+8

2

Hypotenuse = \sqrt{6^2+8^2}Hypotenuse=

6

2

+8

2

Hypotenuse =10Hypotenuse=10

Original height = 10+6 = 16 m

Hence the original height of tree is 16 m

hope it helped you

Answer 2

☆ Solution ☆

Given :-

• A tree is broken at a height of 6 m from the ground and it's top touches the ground at a distance of 8m from the base.

To Find :-

• The original height of the tree .

Step-by-Step-Explaination :-

We are given that a tree is broken at a height of 6 m from the ground

So, Right triangle is formed

So, Perpendicular = 6 m

Its top touches the ground at a distance of 8 m from the base of the tree.

So, Base = 8 m

As we know that :-

Hypotenuse² = Perpendicular² + Base²

Putting the respective value

Hypotenuse² = 6² + 8²

Hypotenuse = √6² + 8²

Hypotenuse = 10

Original height = 10+6 = 16 m

Hence,

The original height of tree is 16 m.