Question

A tree is broken at a height of 6 metre from the the ground at a branches torches the ground at a distance of 8 meter from the base of the tree find the original height of a tree

Answer 1

Answer:

16 m

Step-by-step explanation:

We are given that a tree is broken at a height of 6 m from the ground

So, Right triangle is formed

So. Perpendicular = 6 m

Its top touches the ground at a distance of 8 m from the base of the tree.

So, Base = 8 m

Hypotenuse^2 = Perpendicular^2+Base^2

Hypotenuse^2 = (6)^2+(8)^2

Hypotenuse = √{6^2+8^2}

Hypotenuse =√(36+64)=√100

Hypotenuse=10

•Original height = 10+6 = 16 m

Hence the original height of tree is 16 m

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Hope it helped (◕ᴗ◕✿)