Question

a Tree is broken at a height of 8 m from the ground and it's too touches the ground at a distance of 15 m from the base of the tree. find the original height of the tree

Answer 1

H^2= B^2+ P^2
H^2= 15^2+ 8^2
H^2= 225 m^2+ 64 m^2
H^2= 289 m^2
H= under root of289 m^2
H= 17 m
Final height of tree= 17m+ 8m= 25m