Question

a tree is broken at a height of 8 m from the ground and its top touches the ground at a distance of 15 m from the base of the tree find the original height of the tree.

Answer 1

AB=8m
BC=15
AC=ROOT OF 264
AC=16.24
The original hight of the tree is 16.24m

Answer 2

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Here is your answer
Broken height from ground = 8 m
Base = 15 m
Let the broken height of the tree = x

So by using Pythagoras Theorem

${x}^{2} = (15) {}^{2} + 8 {}^{2} \\ {x}^{2} = 225 + 64 \\ {x}^{2} = 289 \\ x = \sqrt{289} \\ x = 17 \: m$
Therefore Original height of the tree is
= 8 + 17
= 25 m

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