A tree is broken at a height of 8m from the ground and its top touches the ground at a distance of 15m from the base of the tree . Find the original height of the tree
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Step-by-step explanation:
mayankrawal2003:
And the part which was already there was 8cm
So the sum was 25 cm
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and we have to find the total length of tree
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tree is perpendicular to the ground.=8
distance from ground to base of tree= 15cm
on applying pythagoras theorem, we can find hupotenuse
H^2= P^2+B^2
H^2= (15)^2+ (8)^2
H^2= 225+64
H^2= 289
H= plus minus 17
height of tree= 17+8=25
hope it helps you.
please mark it as brainliest.
distance from ground to base of tree= 15cm
on applying pythagoras theorem, we can find hupotenuse
H^2= P^2+B^2
H^2= (15)^2+ (8)^2
H^2= 225+64
H^2= 289
H= plus minus 17
height of tree= 17+8=25
hope it helps you.
please mark it as brainliest.
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