Question

a tree is broken at a height of 9cm from the ground and its top touches the ground at a distance of 12m from the base of the tree. find the orignal height of the tree​

Answer 1

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)

2

+(AB)

2

+(BC)

2

⇒(AC)

2

=(12)

2

+(5)

2

⇒(AC)

2

=144+25

⇒(AC)

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.

Answer 2

Answer:

Step-by-step explanation:

Height Of Tree = 9cm.

It Touches The Ground At A  Distance of 12m.

(12+9)cm = 21cm.