Question

A tree is broken at aheight of 5m from the ground at a distance 12m from the base of the tree. find the original height of the tree​

Answer 1

Answer:

18 m

Step-by-step explanation:

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Answer 2

Answer:

Using given instructions, draw a figure. Let AC be the broken part of the tree. Angle C = 30°

BC = 8 m

To Find: Height of the tree, which is AB

C:\Users\User\Desktop\NCERT\images\trigprob2.jpg

From figure: Total height of the tree is the sum of AB and AC i.e. AB+AC

In right ΔABC,

Using Cosine and tangent angles,

cos 30° = BC/AC

We know that, cos 30° = √3/2

√3/2 = 8/AC

AC = 16/√3 …(1)

Also,

tan 30° = AB/BC

1/√3 = AB/8

AB = 8/√3 ….(2)

Therefore, total height of the tree = AB + AC = 16/√3 + 8/√3 = 24/√3 = 8√3 m.

this is the answer.....

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