Question

A tree is broken at height of 5 m from the ground and it's top
touches the ground at a distance of 12m from the base of the tree. Find the original height of the tree.
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Answer 1

Answer:

18m

Step-by-step explanation:

Let A’CB be the tree before it broken at the point C and let the top A’ touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B.

AB = 12 m and BC = 5 m

Using Pythagoras theorem,

In ΔABC

(AC)²=(AB)²+(BC)²

(AC)²=(12)²+(5)²

(AC)²=144+25

(AC)²=169

AC = √169

AC= 13 m

Hence, the total height of the tree(A’B) = A’C + CB = 13 + 5 = 18 m

Hope this will help you...

Answer 2

Answer:

original height of tree is 18 metre