a tree is broken at height of 7m from the ground and it's top touches the ground at a distance of 24m from the base of the tree . find the original height of the tree.
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let the broken part of tree be x
then total height of tree=7+x
since it form a right angled triangle with base 24m and height 7m and hypotenuse be x
then by using Pythagoras theorem
(hypotenuse)^2=(base)^2+(height)^2
x^2=24^2+7^2
x^2=576+49
x^2=625
x=25
therefore height of tree =x+7=25+7=31
therefore the total is 31
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