Question

a tree is broken at height of8 m from the ground and its top touches at a distance of 15m from the base of the tree find the height of the tree

Answer 1

$\sqrt{ {8}^{2} + {15}^{2} }$
$= \sqrt{289}$
$= \sqrt{ {17}^{2} }$
$= 17$
so the height of the tree is (17+8)m.=25m.