Question

A tree is broken at the height of 5m from the ground and its top touches the ground at a distance of 12m from the Base of the tree. Find the original height of the tree.​

Answer 1

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)

2

+(AB)

2

+(BC)

2

⇒(AC)

2

=(12)

2

+(5)

2

⇒(AC)

2

=144+25

⇒(AC)

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.

Step-by-step explanation:

please mark me as brainliest

Answer 2

Answer:

18m

Step-by-step explanation:

Let the length part of the tree touching the ground be x

The base of the tree and ground make 90° angle

∴Using pythagoras theorem, (5)^2 + (12)^2 +x^2

⇒25+144=x^2

∴169=x^2

∴x=13

Original height of tree= 13 +5= 18m