A tree is broken at the height of 7m from the ground and its top touches the ground at a distance of 24m from the base of tree. Find the original height of the tree.
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let the broken part of tree be xthen total height of tree=7+x
since it form a right angled triangle with base 24m and height 7m and hypotenuse be xthen by using Pythagoras theorem (hypotenuse)^2=(base)^2+(height)^2x^2=24^2+7^2x^2=576+49x^2=625x=25
therefore height of tree =x+7=25+7=31
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