a tree is broken atthe height of 5 m from the ground and its top touches the ground at the distance of 13 m from the base of the tree
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let be the tree BP
BP =BA+AP
=BA + AC
IN angle BAC
5²+12²=AC²
25+144=AC²
169=AC²
AC=13
height of the tree is BA+AP=5+13=18m
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