Question

A tree is broken by the wind but does not separate. If the point from where it breakes is 9m above the ground and its top touches the ground at a distance of 12m from its foot. Findout the total height of the tree before it broke

Answer 1

Answer:

24 m

Step-by-step explanation:

So the diagram is provided, (ignore the calculations above the diagram)

Now if we concentrate on the diagram we can see that the tree has taken a right angled triangle's shape .

So on this we can apply the Pythagoras theorem

[tex]hypotenuses  + 9 =  total height  

Now, Hypotenuses =  √ ((9)² + (12)²)

So hypotenuses = √(225)

                            = 15 m

So cutting back to  Hypotenuse  + 9 = height

The total height of the tree shall be 15 +9 = 24 m

Answer 2

Answer:

24m

Step-by-step explanation:

So, point from where it broke was 9m above the ground.

Its top touched the ground at a distance of 12m.

So according to Pythagoras Theorem,

a sq. + b sq. = c sq.

9sq. + 12sq. = c sq.

81 + 144 = c sq.

225 = c sq.

15 = c

C=15m

So the height will be = 15+9=24m.(ans)