Question

A tree is broken by the wind .The top touched the ground making an 30'and at a distance of 30m from the root of the tree .What was the height of the tree(â3=1.73)

Answer 1

the height of standing part of the tree be = h 

the height of  fallen part (forms hypotenuse) be = x

then the total height of the tree will be = h + x 

now, 

tan 30 = h/30 m

    1/√3 = h/30 m 

   30/√3 = h

   ⇒ h= 30/√3 m           ..... 1

similarly, 

cos 30 = 30 m/ x 

  √3/2 = 30 / x

√3x = (30)2 

 √3x = 60 m 

⇒ x = 60 / √3 m           ......2

      ( we now have both value of h and x )

  on adding equation1 & 2 :

 ⇒ h + x = 30 /√3 +60 /√3

        =90 /√3 m 

        = 60√3 m

so , the total height of the tree is 60√3 m .

Answer 2

Answer:

Step-by-step explanation: