A tree is broken by wind if the point where is broken is 9 m above the ground and it top touch the ground is 12m from its top what is the height of the tree where it's broken
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Unbroken part of the tree makes a right angle with the ground.
Unbroken part of the tree, broken part of the tree and the distance between the tip of the tree and the bottom of the tree forms a right angled triangle.
Unbroken part of the tree forms the hypotenuse of the triangle.
Let the length of the broken part of the tree = x
Length of the unbroken part of the tree = 6 m
Distance between the tip of the tree and bottom of the tree = 8 m
⇒ x2 = 62 + 82
⇒ x2 = 36 + 64
⇒ x2 = 100
⇒ x =√100
⇒ x = 10
So, the length of the unbroken part of the tree = 10 m
Therefore, the total length of the tree before it was broken = 6 + 10 = 16 m
Unbroken part of the tree, broken part of the tree and the distance between the tip of the tree and the bottom of the tree forms a right angled triangle.
Unbroken part of the tree forms the hypotenuse of the triangle.
Let the length of the broken part of the tree = x
Length of the unbroken part of the tree = 6 m
Distance between the tip of the tree and bottom of the tree = 8 m
⇒ x2 = 62 + 82
⇒ x2 = 36 + 64
⇒ x2 = 100
⇒ x =√100
⇒ x = 10
So, the length of the unbroken part of the tree = 10 m
Therefore, the total length of the tree before it was broken = 6 + 10 = 16 m
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