Question

A tree is broken by wind in two parts such that the ratio of length of these two parts is 3/2 : 5/3 . If the smaller part of tree is 4.5m, find the Length of the second part of the tree.

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Answer 1

5 m

Step-by-step explanation:

Let the Total length of Tree be x.

So, Ratio = 3/2x : 5/3x

Now,

$\frac{3}{2} x = 4.5 \\ x = 4.5 \times \frac{2}{3} \\ \\ x = 3.0 = 3 m$

again,

$= \frac{5}{3}x \\ \\ = \frac{5}{3} \times 3 \\ \\ = 5$

Therefore, The length of second part of tree is 5m.

Answer 2

Answer:

Hope this answer is thank full

Step-by-step explanation:

Let AC is the broken part of the tree and AB is standing part.

Given that:

BC=20 m   ∠ACB=30∘

Solution:

In △ABC

tan∠ACB=BCAB

or, tan30∘=20 mAB

or, AB=20 m×31=320m

Similarly,

cos30∘=ACBC

or, AC=cos30∘20 m

or, AC=320 m×2

or, AC=340m

Total length of the tree =AB+AC=320m+340m=3