Question

A tree is broken by wind, its upper part touches the ground at a point 10 metres from the foot of the tree and makes an angle 60° with the ground. The entire length of the tree is​

Answer 1

Answer:

Lenght of the tree =BT=BC+CT

= BC+AC

= ABtan60

0

+AB cosec60

0

=AB(

3

+

3

2

)=10(1+

3

2

)

3

m

=(10+

3

20

)

3

m

Answer 2

Answer:

Let BC be the distance frm the foot of the tree where the top touches

Let AC be broken part

Let AB be still tree part

AB/BC=tan 45

AB/BC =1

AB=BC

SO, AB = 10 M

AB/AC=sin 45

10/AC=1/√2

AC=10√2m

height of the tree = AB+AC

= 10+10√2

=10(1+√2)m

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