Question

A tree is broken by wind.The top touched the ground making an angle of 30°m from foot of tree.What was height of tree?
(√3=1.73)

Answer 1

Answer:

Mtep-by-step explanation:distance between the foot of the tree and the broken part of the tree that touches the ground = 30 m 

let , 

the height of standing part of the tree be = h 

the height of  fallen part (forms hypotenuse) be = x

then the total height of the tree will be = h + x 

now, 

tan 30 = h/30 m

     1/√3 = h/30 m 

    30/√3 = h

    ⇒ h= 30/√3 m           ..... 1

similarly, 

cos 30 = 30 m/ x 

   √3/2 = 30 / x

√3x = (30)2 

 √3x = 60 m 

⇒ x = 60 / √3 m           ......2

       ( we now have both value of h and x )

   on adding equation1 & 2 :

 ⇒ h + x = 30 /√3 +60 /√3

         =90 /√3 m 

         = 60√3 m

so , the total height of the tree is 60√3 m .