Math, asked by bishnupriyamohanty80, 3 months ago

A tree is broken from a height of 12m from the ground and it's top touches the ground 16m away from it's base. What was the original height of the tree ?​

Answers

Answered by premkumarcp
1

Answer:

Angle formed by the tree must be right angle

So it must be in the triangle form

square of hypoteniuos is equal to sum of square of the opposite side and adjacent side

2 2 2

AB = BC + AC

Let AC =16m

BC =12m

2 2 2

AB = (16) + (12)

2

AB =400

2 2

AB = (20)

AB = 20

Height of broken part + Height from the tree broken= height of the tree

20+12=32m

Height of the tree is 32m

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