A tree is broken from a height of 12m from the ground and it's top touches the ground 16m away from it's base. What was the original height of the tree ?
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Angle formed by the tree must be right angle
So it must be in the triangle form
square of hypoteniuos is equal to sum of square of the opposite side and adjacent side
2 2 2
AB = BC + AC
Let AC =16m
BC =12m
2 2 2
AB = (16) + (12)
2
AB =400
2 2
AB = (20)
AB = 20
Height of broken part + Height from the tree broken= height of the tree
20+12=32m
Height of the tree is 32m
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