Question

A tree of height 12m breaks due to storm at certain height and the broken part bends so that the top of the tree touches the ground by making an angle 60*with it find the height at which the tree breaks

Answer 1

Answer: 24$\sqrt{3}$ + 36 m.

Step-by-step explanation: sin 60 = $\sqrt{3}$/2

Also, sin = opposite side/hypotenuse

As the tree forms a right angle with the ground, the ratio of it's new height to the part broken off the tree would be = sin 60.

Let the new height be x.

So, x/(12 - x) = opp. side/ hypotenuse = sin 60 = $\sqrt{3}$/2

So, 2x = 12$\sqrt{3}$ -

=) (2 - $\sqrt{3}$) x  = 12

And x = 12$\sqrt{3}$ / 2 -

= 12$\sqrt{3}$ (2 +

= 24$\sqrt{3}$ + 36 m.