Question

A tree of height 20m breaks at a point 5 m high from the foot of the tree touching the ground at a point, then the distance between the foot of the tree and top of the tree is​

Answer 1

Solution :-

given that,

→ Tree breaks at a point of 5 m high from the foot = Perpendicular height is 5 m .

→ Broken tree part which touches the ground = Hypotenuse length is (20 - 5) = 15 m .

→ Distance between the foot of the tree and the top = Let x m { Base . }

using pythagoras theorem we get,

→ Base = √[Hypotenuse² - Perpendicular²]

→ x = √[15² - 5²]

→ x = √(225 - 25)

→ x = √(200)

→ x = 10√2 m (Ans.)

Learn more :-

The diagram shows two planks are slanted on a vertical wall.

Express cot x in terms of p.

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Answer 2

Answer:

10 root 2

Step-by-step explanation:

20-5=15

h²=p²+b²

b²=p²-h²