Question

A tree of height 20m breaks at a point 5 m high from the foot of the tree touching the ground at a point, then the distance between the foot of the tree and top of the tree is
a)2V10m (b)10/2m (c) 200m (d)2V100m​

Answer 1

Answer:

d) 2V200

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Step-by-step explanation:

the tree will form the two sides of a right angled triangle. the length of one side is 5m and the length of the hypotenuse is 20m-5m = 15m

to find the distance between the foot of the tree and the top of the tree can be calculated using the pythagoras theorem.

a² + b² = c²

here, let a be the side we know of and c is the hypotenuse.

5² + b² = 15²

25 + b² = 225

b² = 225 - 25

b² = 200

b = square root of 200

Answer 2

Given : A tree of height 20m breaks at a point 5 m high from the foot of the tree touching the ground at a point,  

To Find : the distance between the foot of the tree and top of the tree is

Solution:

the foot of the tree touching the ground at a point,  

Hence foot of the tree and top of the tree  both are at ground

Height of tree after break =  5 m

Length of broken part of tree = 20 - 5 = 15 m

Applying Pythagorean theorem

distance between the foot of the tree and top of the tree is  

= √15² - 5²

= 5√3² - 1

= 5√9 - 1

= 5√8

= 10√2 m

 

distance between the foot of the tree and top of the tree is  10√2 m

 

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