A tree of height 20m breaks at a point 5 m high from the foot of the tree
touching the ground at a point, then the distance between the foot of the tree
and top of the tree is
Answers
Given : A tree of height 20m breaks at a point 5 m high from the foot of the tree touching the ground at a point,
To Find : the distance between the foot of the tree and top of the tree is
Solution:
the foot of the tree touching the ground at a point,
Hence foot of the tree and top of the tree both are at ground
Height of tree after break = 5 m
Length of broken part of tree = 20 - 5 = 15 m
Applying Pythagorean theorem
distance between the foot of the tree and top of the tree is
= √15² - 5²
= 5√3² - 1
= 5√9 - 1
= 5√8
= 10√2 m
= 14.14 m
distance between the foot of the tree and top of the tree is 10√2 m
≈ 14.14 m
Learn More:
using the concept of Pythagoras theorem construct a segment of ...
brainly.in/question/8399081
draw a tangent segment of length √12 cm the circle with centre o ...
brainly.in/question/13741684