Question

A triangle ABC can be contructed in which angle B=120, angle C=60 and AB+BC+CA=12 CM ​

Answer 1

Answer:

1 draw a line segment PQ=11 cm.

2 at P canstruct an angle of 60° and at Q an angle of 45°.

3 bisect these angle. let the bisectors DE of AP to intersect QP at B and FG oc AQ to intersect PQ at C.

5 join AB and AC .

Then, ABC is required triangle.

Step-by-step explanation:

Answer 2

Answer:

Suno pehle 12 cm ki line draw Karo phir undono par 120 aur 60 degree ke angle banao aur Dono ko bisect karke 60 degree aur 30 degree aur undono lines ko extend Karo phir jahaa Vo milengi us point se 12 cm Wali line par arc lagao (Dono line ke Dono points se) then join that point with those points (where arcs drawn )