Question

A triangle ABC has vertices A -2,-4 B 10,1 and C 3,8 find the length of the sides AB and AC.Show that the triangle is isosceles.

Answer 1

Step-by-step explanation:

length of side when two vertices are given

√(x1-x2)^2+(y1-y2)^2

then AB length=13

length of AC=13

length of AC=length of AB